Things to note:
* although H1X=9 MHz and H2X= 1MHz the coincidence H1X*H2X=3 MHz. That should be impossible. The H1X gate is ~ 5ns, the H2X gate is 30 ns. Thus assuming 1 MHz good coincidence rate and 8MHz accidentals on H1X, the coincidence rate should be 1 MHz + 1 MHz * 8 MHz * 35 ns = 1.28 MHz. Need to measure this again!
* (H1X*H2X*WC) * ENGE = 11.5 kHz
* setting a veto on the above reduces it at most to 4.6 kHz for
ACthr=-10mV and AC (1/3)
Figure 1
Figure 2
