Elong-13-09-18

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Optimizing Azz in QE and x>1 Range

Beam Energy = 2.2 GeV


HMS

2013-09-18-e022-hms.gif

SHMS

2013-09-18-e022-shms.gif

Beam Energy = 4.4 GeV

HMS

2013-09-18-e044-hms.gif

SHMS

2013-09-18-e044-shms.gif

Beam Energy = 6.6 GeV

HMS

2013-09-18-e066-hms.gif

SHMS

2013-09-18-e066-shms.gif

Beam Energy = 8.8 GeV

HMS

2013-09-18-e088-hms.gif

SHMS

2013-09-18-e088-shms.gif

Beam Energy = 11.0 GeV

HMS

2013-09-18-e110-hms.gif

SHMS

2013-09-18-e110-shms.gif

Optimization Results

Beam Energy = 2.2 GeV

2013-09-19-e022-opt-hms.png2013-09-19-e022-opt-shms.png

Beam Energy = 4.4 GeV

2013-09-19-e044-opt-hms.png2013-09-19-e044-opt-shms.png

Beam Energy = 6.6 GeV

2013-09-19-e066-opt-hms.png2013-09-19-e066-opt-shms.png

Beam Energy = 8.8 GeV

2013-09-19-e088-opt-hms.png2013-09-19-e088-opt-shms.png

Beam Energy = 11.0 GeV

(None for HMS -- rates drop off dramatically by the time it's in a good kinematics range) 2013-09-19-e110-opt-shms.png

Fixed uncertainty due to large asymmetry

Previously, the code was using a simplified $\delta A_{zz} = \frac{4}{f \cdot Pzz \sqrt{N}}$. This gave all of the above uncertainties, as well as this one:

2013-09-19-old-error.png

Going back through the uncertainty tech note, the assumption of a small asymmetry isn't made until after Eq. 28. Utilizing the full uncertainty (Eq. 28 and 25), $\delta A_{zz} = \frac{2}{f \cdot Pzz}\sqrt{\frac{N_{Pol}}{N_u^2}+\frac{N_{Pol}^2}{N_u^3}}$, the uncertainties change (very slightly) to:

2013-09-19-new-error.png

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