Elong-13-05-01-Azz-Method-2

A_zz Formalism - Method 2

Target Material = ND3

$z_{\mathrm{tgt}} = 3\mathrm{ cm}$

$p_f = 0.65$

$P_{zz} = 20\%$

$N_{A} = 6.0221413\cdot 10^{23}$

$\rho_{\mathrm{He}} = 0.1412 \mathrm{g/cm}^3$

$M_{\mathrm{He}} = 4.0026 \mathrm{g/mole}$

$\rho_{\mathrm{ND}_3} = 1.007 \mathrm{g/cm}^3$

$M_{\mathrm{ND}_3} = 20 \mathrm{g/mole}$

$I_{\mathrm{beam}} = 0.115 \mathrm{\mu A}$

$\delta F_1^d = 5\%$

(1)	$R_{\mathrm{Total}} = \mathcal{A}\left[ \mathcal{L}_{\mathrm{He}}\left( \frac{d^2\sigma_{\mathrm{He}}^u}{d\Omega dE'}\right) + \mathcal{L}_{\mathrm{N}}\left( \frac{d^2\sigma_{\mathrm{N}}^u}{d\Omega dE'}\right) + \mathcal{L}_{\mathrm{D}}\left( \frac{d^2\sigma_{\mathrm{D}}}{d\Omega dE'}\right) \right]$
(2)	$R_{\mathrm{Total}} = \mathcal{A}\left[ \mathcal{L}_{\mathrm{He}}\left( \frac{d^2\sigma_{\mathrm{He}}^u}{d\Omega dE'}\right) + \mathcal{L}_{\mathrm{N}}\left( \frac{d^2\sigma_{\mathrm{N}}^u}{d\Omega dE'}\right) + \mathcal{L}_{\mathrm{D}}\left( \frac{d^2\sigma_{\mathrm{D}}^u}{d\Omega dE'}\left[ 1 + \frac{1}{2}P_{zz}A_{zz}^d \right]\right) \right] $
(2a)	$R_{\mathrm{Total}} = \mathcal{A}\left[ \mathcal{L}_{\mathrm{He}} \sigma_{\mathrm{He}}^u + \mathcal{L}_{\mathrm{N}} \sigma_{\mathrm{N}}^u + \mathcal{L}_{\mathrm{D}} \sigma_{\mathrm{D}}^u\left( 1 + \frac{1}{2}P_{zz}A_{zz}^d \right) \right] $

where

(3)	$\mathcal{A} = \left( \Delta\Omega \Delta E' \right)$
(4)	$\mathcal{L}_{\mathrm{He}} = \left[ \mathcal{N}_A \frac{\rho_{\mathrm{He}}}{M_{\mathrm{He}}}\left(1 - p_f\right) \right] \cdot \left( \frac{I_{\mathrm{beam}}}{e} \right) \cdot z_{\mathrm{tgt}}$
(5)	$\mathcal{L}_{\mathrm{N}} = \left[ \mathcal{N}_A \frac{\rho_{\mathrm{ND}_3}}{M_{\mathrm{ND}_3}} p_f \right] \cdot \left( \frac{I_{\mathrm{beam}}}{e} \right) \cdot z_{\mathrm{tgt}}$
(6)	$\mathcal{L}_{\mathrm{D}} = 3\left[ \mathcal{N}_A \frac{\rho_{\mathrm{ND}_3}}{M_{\mathrm{ND}_3}} p_f \right] \cdot \left( \frac{I_{\mathrm{beam}}}{e} \right) \cdot z_{\mathrm{tgt}}$
(7)	$\sigma^u_X = \frac{d^2\sigma^u_X}{d\Omega dE'} = A_X \left( \frac{d\sigma}{d\Omega} \right) _{\mathrm{Mott}_{\mathrm{p}}} \left[ \frac{2\cdot \left(\frac{F_1^{X}}{A_X} \right)}{m_{p}}\tan^2\left( \frac{\theta_{e'}}{2} \right) + \frac{\left( \frac{F_2^X}{A_X}\right) }{\nu} \right]$
(8)	$\left( \frac{d\sigma}{d\Omega} \right) _{\mathrm{Mott}_{\mathrm{p}}}=\frac{1^2 \alpha^2 \hbar^2 c^2}{4E^2\sin^4\left( \frac{\theta}{2} \right)}\cos^2\left( \frac{\theta}{2} \right)$
(9)	$\sigma_D = \frac{d^2\sigma_{\mathrm{D}}}{d\Omega dE'} = \frac{d^2\sigma_{\mathrm{D}}^u}{d\Omega dE'}\left[ 1 + \frac{1}{2}P_{zz}A_{zz}^d \right] $

Then

(10)	$N_{Pol} - N_{u} = R^{Pol}_{\mathrm{Total}}t^{Pol}_{\mathrm{Total}} - R^{u}_{\mathrm{Total}}t^{u}_{\mathrm{Total}} $
(11)	$N_{u} = R^{u}_{\mathrm{Total}}t^{u}_{\mathrm{Total}} $

If we assume that $t^{Pol}_{\mathrm{Total}} \approx t^{u}_{\mathrm{Total}} \approx t$, then

(12)	$N_{Pol} - N_{u} = \left( R^{Pol}_{\mathrm{Total}} - R^{u}_{\mathrm{Total}}\right) t $
(13)	$N_{Pol} - N_{u} = \left( \mathcal{A}\left[ \mathcal{L}_{\mathrm{He}} \sigma_{\mathrm{He}}^u + \mathcal{L}_{\mathrm{N}} \sigma_{\mathrm{N}}^u + \mathcal{L}_{\mathrm{D}} \sigma_{\mathrm{D}}^u\left( 1 + \frac{1}{2}P_{zz} A_{zz}^d \right) \right] - \mathcal{A}\left[ \mathcal{L}_{\mathrm{He}} \sigma_{\mathrm{He}}^u + \mathcal{L}_{\mathrm{N}} \sigma_{\mathrm{N}}^u + \mathcal{L}_{\mathrm{D}} \sigma_{\mathrm{D}}^u \right] \right) t $
(13a)	$N_{Pol} - N_{u} = \left( \mathcal{A}\mathcal{L}_{\mathrm{D}}\sigma_{\mathrm{D}}^u \left( \frac{1}{2}P_{zz} A_{zz} \right) \right) t$
(14)	$N_{u} = R^{u}_{\mathrm{Total}}t $
(15)	$N_{u} = \mathcal{A}\left[ \mathcal{L}_{\mathrm{He}} \sigma_{\mathrm{He}}^u + \mathcal{L}_{\mathrm{N}} \sigma_{\mathrm{N}}^u + \mathcal{L}_{\mathrm{D}} \sigma_{\mathrm{D}}^u \right]t $
(16)	$\frac{N_{Pol} - N_{u}}{N_{u}} = \left( \frac{\mathcal{L}_{\mathrm{D}}\sigma_{\mathrm{D}}^u}{ \mathcal{L}_{\mathrm{He}} \sigma_{\mathrm{He}}^u + \mathcal{L}_{\mathrm{N}} \sigma_{\mathrm{N}}^u + \mathcal{L}_{\mathrm{D}}\sigma_{\mathrm{D}}^u } \right) \frac{1}{2} A_{zz} P_{zz}$
(17)	$\frac{N_{Pol} - N_{u}}{N_{u}} = f \frac{1}{2} A_{zz} P_{zz}$
(18)	$A_{\mathrm{meas}}^{(2)} = \frac{N_{Pol} - N_{u}}{N_{u}}$
(18a)	$A_{\mathrm{meas}}^{(2)} = f \frac{1}{2} A_{zz} P_{zz}$
(19)	$A_{zz} = \frac{2 }{f \cdot P_{zz}}A_{\mathrm{meas}}^{(2)}$

In order to get the uncertainty, we'd use

(20)	$\delta A_{zz} = \sqrt{\left( \frac{\partial A_{zz}}{\partial A_{\mathrm{meas}}^{(2)}} \delta A_{\mathrm{meas}}^{(2)} \right)^2 + \left( \frac{\partial A_{zz}}{\partial f} \delta f \right)^2 + \left( \frac{\partial A_{zz}}{\partial P_{zz}} \delta P_{zz} \right)^2 }$
(20a)	$\delta A_{zz} = \sqrt{\left( \delta A_{zz}^{\mathrm{Stat}} \right) ^2 + \left( \delta A_{zz}^{\mathrm{Dil}} \right) ^2 + \left( \delta A_{zz}^{\mathrm{Pol}} \right) ^2 }$
(20b)	$\delta A_{zz} = \sqrt{\left( \delta A_{zz}^{\mathrm{Stat}} \right) ^2 + \left( \delta A_{zz}^{\mathrm{Sys}} \right) ^2 }$

Ignoring $\delta A_{zz}^{\mathrm{Sys}}$ for now (and in all of the plots I'm showing), then

(21)	$ \delta A_{zz}^{\mathrm{Stat}} = \frac{\partial A_{zz}}{\partial A_{\mathrm{meas}}^{(2)}} \delta A_{\mathrm{meas}}^{(2)} = \frac{2}{f\cdot P_{zz}} \delta A_{\mathrm{meas}}^{(2)} $
(22)	$ \delta A_{\mathrm{meas}}^{(2)} = \sqrt{ \left( \frac{\partial A_{\mathrm{meas}}^{(2)}}{\partial N_{Pol}} \delta N_{Pol} \right)^2 + \left( \frac{\partial A_{\mathrm{meas}}^{(2)}}{\partial N_{u}} \delta N_{u} \right)^2 }$
(23)	$ \delta A_{\mathrm{meas}}^{(2)} = \sqrt{ \left( \frac{1}{N_u} \sqrt{N_{Pol}} \right)^2 + \left( -\frac{N_{Pol}}{N_u^2} \sqrt{N_u} \right)^2 }$
(24)	$ \delta A_{\mathrm{meas}}^{(2)} = \sqrt{ \frac{N_{Pol}}{N_u^2} + \frac{N_{Pol}^2}{N_u^3} }$

If we assume that $N_{Pol} \approx N_u \approx \frac{N}{2}$, then

(25)	$ \delta A_{\mathrm{meas}}^{(2)} = \sqrt{ \frac{N/2}{N^2/4} + \frac{N^2/4}{N^3/8} }$
(25a)	$ \delta A_{\mathrm{meas}}^{(2)} = \sqrt{ \frac{2}{N} + \frac{2}{N} }$
(25b)	$ \delta A_{\mathrm{meas}}^{(2)} = \frac{2}{\sqrt{N}}$

which would yield

(26)	$ \delta A_{zz}^{\mathrm{Stat}} = \frac{2}{f\cdot P_{zz}} \delta A_{\mathrm{meas}}^{(2)} $
(26a)	$ \delta A_{zz}^{\mathrm{Stat}} = \frac{2}{f\cdot P_{zz}} \left( \frac{2}{\sqrt{N}} \right) $
(27)	$ \delta A_{zz}^{\mathrm{Stat}} = \frac{4}{f\cdot P_{zz}\sqrt{t\cdot R_{\mathrm{Total}}}} $

Using the same formalism that HERMES used (which defines $F_{1_{\mathrm{HERMES}}}^d = \frac{(1 + Q^2/\nu^2)F_2^d}{2x(1+R)}$ with $F_2^d=\frac{F_2^p + F_2^n}{2}$ as a per nucleon quantity, which corresponds to the Bosted that uses per nucleus by $F_{1_{\mathrm{HERMES}}}^d = \frac{F_{1_{\mathrm{Bosted}}}^d}{A_{\mathrm{D}}} = \frac{F_1^d}{2}$ -- as described previously), we can extract $b_1^d$ and its uncertainty by

(18)	$ b_1^d = - \frac{3}{2}A_{zz} \left( \frac{F_1^d}{A_{\mathrm{D}}} \right)= - \frac{3}{2}A_{zz} \left( \frac{F_1^d}{2} \right)$
(19)	$ \delta b_1^d =\sqrt{ \left(\frac{\partial b_1^d}{\partial A_{zz}} \delta A_{zz} \right)^2 + \left(\frac{\partial b_1^d}{\partial F_1^d} \delta F_1^d \right)^2 }$
(19a)	$ \delta b_1^d =\sqrt{ \left[ - \frac{3}{2} \left( \frac{F_1^d}{2} \right)\delta A_{zz} \right]^2 + \left[ - \frac{3}{2} A_{zz} \left( \frac{1}{2} \right)\delta F_1^d \right]^2 }$

Plots with using A_zz Method 2 Calculations

Total Rates

Ignoring our W>2 physics cut, then our total rates come out to:

Comparing F1 from PDFs and Bosted

Note: For the plots below, Phys Rate = D2 Rate Only

The plot below uses F1 calculated per nucleon from the PDF code, not from the Bosted code.

If I calculate F1 per nucleon from the Bosted code, I get:

Removed arbitrary x cuts

Removing arbitrary cuts on x, which were being used previously, increased the rate we can take at each point. Current estimates, where Phys Rate = D2 + N + He rates, are:

--E. Long 20:59, 3 May 2013 (UTC)